Java EE (Java Enterprise Edition) General Discussion

Hi! This is a simple question: Does JDK 6 Transformer Class support XSLT 2.0?

My problem raise when I use the <xsl:character-map> tag. A Example:

template.xslt

<xsl:stylesheet version="2.0">
<xsl:output method="xml" version="1.0" encoding="UTF-8" use-character-maps="vxml"/>
<xsl:character-map name="vxml">
   <xsl:output-character character="«" string='&lt'/>
   <xsl:output-character character="»" string='&gt'/>
   <xsl:output-character character="¨" string='"'/>
</xsl:character-map>
<xsl:template match="/">
   «vxml version=¨2.0¨»
   .
   {xslt operations...}
   .
   «/vxml»
</xsl:template>
.
.
.
{code}

*someXML.xml*
{code}
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="template.xslt"?>
.
.
.
{code}

Well, when I use external software (Altova XMLSpy), the result is exactly that I want... but, when I use a simple java class with Transformer (in java 6), the result contains alternative char and no the correct character that character-map is supposed to change.

Then, in this forum all people only use XSLT with version="1.0"... and appear my question... Transformer Class in JDK 6 really support XSLT version 2.0? I can't find information of this...

Edited by: MIrribarra on 20-03-2009 05:51 PM

Edited by: MIrribarra on 20-03-2009 05:53 PM
Deleted intensionally semi-colon in "&lt" and "&gt" because editor change string code