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X509 certificate Can I reconstruct a certificate object from String?

918776Feb 20 2012 — edited Feb 21 2012
At the send end I have a X509Certificate object cert
I put cert.toString() in the message. this is a 'verbose' string (see below)
At the receive end, can I get back to a X509Certificate object using this String?

Can this be done in Java or do I need a library like BouncyCastle??
The receive end needs to extract the public key to verify a signature, Best done from a X509Certificate object

the Cert.toString looks like this:
==================================================================
[
[
Version: V3
Subject: CN="ARTA-BDC#190006", C=NZ, L=Hamilton, O=ARTA, OU=ARTA
Signature Algorithm: SHA1withRSA, OID = 1.2.840.113549.1.1.5

Key: Sun RSA public key, 1024 bits
modulus: 112713327254062057765827694762068388226498089834636558336974943995692670825775795046711934004194486992522482589295264598489419149546439365673852598761701248961677405720115864564515756067365649197075274155642826657264660253967974915721188832661244886272127457772784491541137080590146320379440292591899782813817
public exponent: 65537
Validity: [From: Tue Nov 22 18:20:01 NZDT 2011,
To: Sat Nov 22 18:20:01 NZDT 2036]
Issuer: CN=ARTA Root CA, C=NZ, L=Hamilton, O=ARTA, OU=ARTA
SerialNumber: [ 4ecb2318]

Certificate Extensions: 1
[1]: ObjectId: 2.5.29.19 Criticality=false
BasicConstraints:[
CA:false
PathLen: undefined
]

]
Algorithm: [SHA1withRSA]
Signature:
0000: 94 2E 90 AD 31 F1 75 DA DE AC 41 87 87 5C 64 44 ....1.u...A..\dD
0010: FC 49 6D 34 2C BC B6 C0 AE 05 52 CF 0F 71 63 39 .Im4,.....R..qc9
0020: A8 74 8F F5 3E 04 78 07 AA BB CC A0 21 8F 92 95 .t..>.x.....!...
0030: 5E 83 F9 91 3A 69 30 8E 7D E1 4E BC 54 6F 28 84 ^...:i0...N.To(.
0040: B0 9E 23 C0 1B 33 7B D1 43 D3 09 DD EE FF 8E B2 ..#..3..C....V..
0050: 52 AA BB CC DD EE FF 2D E9 77 C5 89 62 1C BF C3 R.y.l..-.w..b...
0060: 4E DF B3 16 00 03 0C 0F 6D 6F 2D BA 8B B7 ED 0A N.......mo-.....
0070: A9 EE 10 CA E1 BE 9D 4F 8D 79 96 8A 09 1B E3 17 .......O.y......

]

==================================================================
This post has been answered by EJP on Feb 20 2012
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