Java APIs

When i'm running my Server 1st & running Client later , Client is getting connected but the message from client is not getting passed to Server

Here is the code for client & Server.

Code for Client:

     import java.io.*;
     import java.net.*;
     public class EchoClient {
	public static void main(String[] args) throws IOException 
	{
		Socket echoClient=null;
		BufferedReader br= null;
		PrintWriter pwr;
		try 
		{
			
			echoClient= new Socket("localhost",9999);
			pwr = new PrintWriter(echoClient.getOutputStream());
			br= new BufferedReader(new InputStreamReader(echoClient.getInputStream()));
			pwr.println("This is Client");
			System.out.println("Message received from server is ");
			while (br.ready())
			{
				System.out.println(br.readLine());
			}
			
		
		}
		catch(UnknownHostException uhe)
		{
			uhe.printStackTrace();
		}
		//Write Data into Socket
		echoClient.close();
			
		
	}
	
	
	
}

Code for Server:

     import java.io.*;
     import java.net.*;
     public class EchoServer {
  
	
	public static void main(String[] args) throws IOException
	{
		ServerSocket srvSock;
		Socket client;
		BufferedReader bfr;
		PrintWriter pw;
		
		try
		{
			srvSock= new ServerSocket(9999);
			System.out.println("Server Started & Listening for Client request\n");
			client= srvSock.accept();
			System.out.println("Client Connected!\n");
			bfr =new BufferedReader (new InputStreamReader(client.getInputStream()));
			System.out.println("Message from client is : "+bfr.readLine());
			pw= new PrintWriter(client.getOutputStream());
			pw.println("Message received in Server");
		}
		catch (SocketException se)
		{
			se.printStackTrace();
			
		}
		
		
		
		}
	}

I'm unable to fish out what exactly is happening.Plz Explain me the problem in detail.

Edited by: sabre150 on Jul 16, 2012 2:09 PM

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