replace the digits after a string 'CVV' with X
dbuserJul 13 2012 — edited Jul 13 2012Hi,
I am using the oracle 10g, I am trying to write the a sql query by which in a below mention patterns I can replace the digits after a string 'CVV' with X. The no of X will be equal to the no of digits after CVV
1. BTA CVV 8810
2. VISA PARTICULAR CCVIXXXXXXXXXXXX5474/1012 CVV498
3. C***CVV VI 569***
4. dskdfjdkgjdfk: FP CCVI,XXXXXXXXXXXX0031/0711/CVV 063/dffddf:dfdfdfd
5. (T) CVV 4671
6. MS-ACEEML/CVV
7. O/AXXXXXXXXXXXX1007EXP1210/CVVXXXXXXXXXXX4664/MEETING CARD FOR AMEX PARTNER OFFICES
AFTER a change above data should look like as mentioned below
1. BTA CVV XXXX
2. VISA PARTICULAR CCVIXXXXXXXXXXXX5474/1012 CVVXXX
3. C***CVV VI XXX***
4. dskdfjdkgjdfk: FP CCVI,XXXXXXXXXXXX0031/0711/CVV XXX/dffddf:dfdfdfd
5. (T) CVV XXX
6. MS-ACEEML/CVV -- no change for this
7. O/AXXXXXXXXXXXX1007EXP1210/CVVXXXXXXXXXXX4664/MEETING CARD FOR AMEX PARTNER OFFICES --- -- no change for this
Initially I tried to find the position of CVV in any string and then from that position take the digit and replace them with X. I tried the below code which is not complete
select REGEXP_INSTR('BTA CVV XXXX','CVV',1,1) from dual;
Could you please help me in doing this
Regards