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regexp_substr to extract date

733774Feb 9 2010 — edited May 13 2011
I have a field that has date (mm/dd/yyyy format) followed by a new line character. How do I extract just the data from the field using regexp_substr?

I can use substr for this, but i want to see if i can use regexp_substr

Thanks
Billu
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Locked on Jun 10 2011
Added on Feb 9 2010
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