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Range partition on a column with ' TIMESTAMP(6) WITH TIME ZONE DEFAULT SYSTIMESTAMP AT TIME ZONE 'U

rahchaJan 16 2018 — edited Jan 16 2018

ALL,

I am trying to create partition on the a column which is defined as

TIMESTAMP(6) WITH TIME ZONE DEFAULT SYSTIMESTAMP AT TIME ZONE 'US/CENTRAL'

        NOT NULL ENABLE

but getting error

Error report -

ORA-03001: unimplemented feature

03001. 00000 -  "unimplemented feature"

*Cause:    This feature is not implemented.

*Action:   None.

below is the DDL

CREATE TABLE TAB_PIT (

    DATA_ID       NUMBER(10,0)

        NOT NULL ENABLE,

    CREATED_DT    TIMESTAMP(6) WITH TIME ZONE DEFAULT SYSTIMESTAMP AT TIME ZONE 'US/CENTRAL'

        NOT NULL ENABLE,

    CREATED_BY    VARCHAR2(20 BYTE),

    MODIFIED_DT   TIMESTAMP(6) WITH TIME ZONE DEFAULT SYSTIMESTAMP AT TIME ZONE 'US/CENTRAL'

        NOT NULL ENABLE

)

    PARTITION BY RANGE ( CREATED_DT ) INTERVAL ( NUMTOYMINTERVAL(1,'MONTH') ) ( PARTITION P0

        VALUES LESS THAN ( TO_DATE('01-JAN-2006','DD-MON-YYYY') )

    );

Can anybody help me with this issue. I have seen examples where column with LOCAL TIME ZONE have been partitioned.

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Locked on Feb 13 2018
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