SQL & PL/SQL

Hello

Good Day!

My requirement is to split the string into words.

So I need to identify newline charactor and semicolon (;) ,comma and space as terminator for input string.

Please note I'm currently incorporated blank and comma as seperator as shown below.

select regexp_substr('test
to
string into words', '([^,[:blank:]]+)', 1,  1) from dual;

How do i incorporate newline charactor and semicolon in Oracle Regular expression?

Please advise.

Thanks & Regards

Sree