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Math.sqrt()

807606Apr 20 2007 — edited Apr 20 2007
Is there another way to write this?

float fx1 = ( x1 * x1 ) * Math.sqrt ( 9 - ( x1 * x2 ) );

Math.sqrt(double) is correct but, can you not do this?
Use Float maybe?
Thanks!
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Locked on May 18 2007
Added on Apr 20 2007
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