Hello,
I get the following error:
ORA-19202: Error occurred in XML processing
LPX-00607: Invalid reference: 'current-date'.
The XSL looks like:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="2.0" encoding="UTF-8" indent="yes" />
<xsl:template match="*">
<xsl:element name = "today">
<xsl:value-of select="current-date()"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
in https://community.oracle.com/tech/apps-infra/profile/587246
it was stated that xslt 2.0 will be supported for xmltypes: this was stated in 2010.
Any update on that, or how to get the current-date in xsl, using xmltype?
(I am using oracle 12c at the moment)
Thanks,