Java EE (Java Enterprise Edition) General Discussion

I am trying to stream out an xml file which I have in gzip format through a socket. I want to be able to display the xml file in a web browser.

This is what I've tried:
1 - I've written the MIME header: "text/xml content-encoding: gzip" to the outputstream
2 - I've open and read the file and then written it out to the outputstream.

... this is a sample code

OutputStream out; // this is already pointing to my output stream.

File myFile = new File(fileName);
FileInputStream inputFile = new FileInputStream(myFile);
byte[] buffer = new byte[1024];
int bytes = 0;

while (bytes != -1) {
bytes = inputFile.read(buffer);
out.write(buffer,0,bytes);
}
out.flush();


This is my problem:
I get the following error in the browser:
=====================================================
The XML page cannot be displayed
Cannot view XML input using style sheet. Please correct the error and then click the Refresh button, or try again later.
--------------------------------------------------------------------------------
An invalid character was found in text content. Error processing resource 'http://xx.xx.xx.xx/cgi-bin/CGILink?cmd=vfuellog...
======================================================

I think the problem is somehow related to the fact that I am writing an uncompressed string to the outputstream (the MIME header) and then I am sending the compressed information (note: I also tried wrapping my outputstream with a GZIPOutputStream but did not work ... and does not make sense to me to do that anyway - got the exact same error in the browser when I did that).

Can anybody point me in the right direction on how to add the MIME header for a gzip file, and then stream out the gzip file? ... note, I don't want to create a file, but just stream it out. However, for debugging purposes I wrote to a FileOutputStream instead and the created file was perfectly OK (I opened it both with winzip and gzcat).