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How to pass an variable to xmlhttp.open("GET/POST","xmlfile",true) method

876192May 10 2012 — edited May 10 2012
Hi ,


Is it possible to pass a variable instead of providing xml file.

For example

let d='<xml>'+
'<book>'+
'<name>Basker Ville</name>'+
'</book>'+
'</xaml>';

now is it possible xmlhttp.open("GET",d,true); ?

Thanks in advance
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Locked on Jun 7 2012
Added on May 10 2012
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