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How to open a form at a dynamic position ?

YounFeb 26 2016 — edited Feb 26 2016

Hello Apex community,

I have static page and a button on it. The button is expected to open a form at specific dynamic position based on the user connected to the application.

I created a link between the button and the page to open but I can't find how to force the form to open on a dynamic position.

I seems like the link can be created with a static value. Is there a way to create a link with a dynamic value based on SQL query ?

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Does anyone have an idea please ?

Thank you in advance.

Regards,

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Locked on Mar 25 2016
Added on Feb 26 2016
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