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How to insert the current datetime?

hasilvaMar 23 2015 — edited Mar 24 2015

Hello everyone,

I'm beginner in this world, sorry for my simple question.

I wanna insert the current date and time on the database after my application has started the stored procedure.

I have to insert the following format for datetime column: 03/19/2015 00:00:00 (i.e. MM/DD/YYYY XX:XX:XX AM/PM)

Is it correct to use this line?

TO_DATE(SYSDATE, 'MM/DD/YYYY HH24:MI:SS')

--

My SYSDATE example:

SELECT SYSDATE from DUAL;

3/19/2015 5:43:37 PM

-------------

CREATE OR REPLACE PROCEDURE "BD"."PROC" (

p_varCONTACT_INFO NVARCHAR2,

p_varDAILY_FROM NUMBER,

p_varDAILY_TILL NUMBER,

p_varGRUPO_DESTINO VARCHAR2,

p_varPROTOCOLO VARCHAR2,

p_varMCDU VARCHAR2,

p_varCLUSTER_N VARCHAR2,

p_varGRUPO_ORIGEM VARCHAR2,

p_varRP_DESTINO VARCHAR2,

p_varMOTIVO_QUEDA VARCHAR2,

p_varSWITCH_DESTINO VARCHAR2,

p_varACCOUNT_NUMBER_IVR VARCHAR2,

)

AS

BEGIN

INSERT INTO BD.TA_CALLBACK

(

RECORD_ID,

CONTACT_INFO,

CONTACT_INFO_TYPE,

RECORD_TYPE,

RECORD_STATUS,

CALL_RESULT,

ATTEMPT,

DAILY_FROM,

DAILY_TILL,

TZ_DBID,

CHAIN_ID,

CHAIN_N,

GROUP_ID,

SWITCH_ID,

PROTOCOLO,

MCDU,

GRUPO_DESTINO,

RP_DESTINO,

GRUPO_ORIGEM,

MOTIVO_QUEDA,

SWITCH_DESTINO,

DATA,

CAMPO1,

CLUSTER_N

)

SELECT

NVL(MAX(record_id),0) + 1,

p_varCONTACT_INFO,

1,

2,

1,

28,

0,

p_varDAILY_FROM,

p_varDAILY_TILL,

131,

NVL(MAX(chain_id),0) + 1,

0,

8847,

283,

p_varPROTOCOLO,

p_varMCDU,

p_varGRUPO_DESTINO,

p_varRP_DESTINO,

p_varGRUPO_ORIGEM,

p_varMOTIVO_QUEDA,

p_varSWITCH_DESTINO,

TO_DATE(SYSDATE, 'MM/DD/YYYY HH24:MI:SS'),

p_varACCOUNT_NUMBER_IVR,

p_varCLUSTER_N

FROM BD. TA_CALLBACK;

END PROC;

-------------

Environment: Oracle 10g

Best regards,

Henrique Silva

This post has been answered by caadecarvalho on Mar 23 2015
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Added on Mar 23 2015
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