SQL & PL/SQL

Hi Experts,

I was asked to prove that 2222^5555 + 5555^2222 is divisible by 7 (^ denotes 'to the power of').

I was trying to do the same in Oracle SQL/PL-SQL, but I was getting the error "ORA-01426 Numeric Overflow".

Here's my code:

/*=====================================================*/
DECLARE
--
l_num25 binary_double;
l_num52 binary_double;
l_num binary_double;
--
BEGIN
--
SELECT to_binary_double(POWER(2222,5555)) INTO l_num25 FROM dual;
SELECT to_binary_double(POWER(5555,2222)) INTO l_num52 FROM dual;
l_num := MOD((l_num25 + l_num52), 7);
--
dbms_output.put_line(TO_CHAR(l_num));
--
EXCEPTION
--
WHEN OTHERS THEN
raise_application_error(-20000, SUBSTR((SQLERRM
|| '----------'
|| dbms_utility.format_error_backtrace), 1, 400));
--
END;
--[ORA-01426 :: Numeric Overflow]
/*=====================================================*/

Can you guys show me how to do this in SQL or PL/SQL?

TIA,
Hex.