SQL & PL/SQL

Hi,

I have a query with "WITH" CLAUSE , I need to create a view on this query. But I am getting error like

ORA-32034 : Unsupported sue of WITH clause.

Please help me...!!

Please find below my query...!!

WITH RANGE
         AS (SELECT A.MASTERMACHINEID,
                    a.startdate,
                    a.enddate,
                    a.startdate - (1 / 3) + (lvl) * 1 / 3 SHIFT_ST_DT,
                    a.startdate + (lvl) * 1 / 3 AS SHIFT_END_DT,
                    a.quantity,
                    (LEAST ( enddate, TODATE) - GREATEST ( FROMDATE, startdate)) * 24 TOTAL_HRS,
                    (enddate - startdate) * 24 AVAIL,
                   todate,
                   fromdate
              FROM OMP A,
                   (SELECT LEVEL lvl
                      FROM (SELECT MAX (enddate - startdate) AS diff FROM OMPWORKORDER)
                    CONNECT BY LEVEL <= (diff) * 3),
                   MASTER B
             WHERE A.MASTERMACHINEID = B.MASTERMACHINEID 
               AND lvl / 3 <=(enddate - startdate) + 1
            ORDER BY SHIFT_ST_DT)
   SELECT shift_date,
          shift_num,
          shift_hrs,
          DECODE (SIGN (SHUT_DWN_TIME), -1, 0, SHUT_DWN_TIME),
          8 - DECODE (SIGN (SHUT_DWN_TIME), -1, 0, SHUT_DWN_TIME) shift_avail_hrs,
          qty,
          total_qty
     FROM (SELECT TRUNC (SHIFT_ST_DT) shift_date,
                  ROW_NUMBER () OVER (PARTITION BY TRUNC (SHIFT_ST_DT) ORDER BY SHIFT_ST_DT) shift_num,
                  8 shift_hrs,
                  (LEAST ( SHIFT_END_DT, TODATE) - GREATEST ( FROMDATE, SHIFT_ST_DT)) * 24
                    SHUT_DWN_TIME,
                  quantity / (avail - TOTAL_HRS) qty,
                  round(((SHIFT_END_DT - SHIFT_ST_DT) * 24 - (LEAST (SHIFT_END_DT, TODATE) - GREATEST (FROMDATE, SHIFT_ST_DT)) * 24)  * QuantiTY / (AVAIL - TOTAL_HRS),2)
                     TOTAL_QTY
             FROM RANGE A );

Regards
KPR

Edited by: BluShadow on 17-Mar-2011 09:48
added {noformat}

{noformat} tags for readability