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Feedback on sql_id doesn't work

script:

set feedback on sql_id
select * From employees
where employee_id = 100;

run as a script

version : 25.3.2

set feedback on sql_id
select * From employees
where employee_id = 100;
EMPLOYEE_ID FIRST_NAME           LAST_NAME                 EMAIL                     PHONE_NUMBER         HIRE_DAT JOB_ID         SALARY COMMISSION_PCT MANAGER_ID DEPARTMENT_ID
----------- -------------------- ------------------------- ------------------------- -------------------- -------- ---------- ---------- -------------- ---------- -------------
       100 Steven               King                      SKING                     515.123.4567         03/06/17 AD_PRES         24000                                      90
1 row selected.
SQL_ID: amkqwss9x7mad

version: 25.4.0 and newer:

EMPLOYEE_ID FIRST_NAME LAST_NAME EMAIL PHONE_NUMBER HIRE_DAT JOB_ID SALARY COMMISSION_PCT MANAGER_ID DEPARTMENT_ID----------- -------------------- ------------------------- ------------------------- -------------------- -------- ---------- ---------- -------------- ---------- ------------- 100 Steven King SKING 515.123.4567 03/06/17 AD_PRES 24000 90

This post has been answered by thatJeffSmith-Oracle on Mar 6 2026
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