New to Java

Hi All,

Recently I have been trying out exception printing and ran across strange behaviour. I just noticed that e.printStackTrace() actually prints the message at the end of everything...... does any body know why ?

----------------------------------------
here is my code...
------------------------------------------

public class ExceptionTrial
{
	public static void main( String arguments[] )
	{
		try
		{
			int i=1;
			i=i-1;
			int b=3/i;
		}
		catch (Exception e)
		{
			System.out.println( "\nprintStackTrace Should Start here------\n" );
			e.printStackTrace();

			System.out.println( "\nprintStackTrace Should End here------\n" );
		}
	}
}



---------------------
The result
------------------------


printStackTrace Should Start here------


printStackTrace Should End here------

java.lang.ArithmeticException: / by zero
				at ExceptionTrial.main(ExceptionTrial.java:10)

????????????????? Why is it printing the message at the end ???????????