Cos inverse
807605Oct 6 2007 — edited Oct 6 2007Hi,
I need some help with figuring out the cos inverse function in java. I can find the cos function but i can't find the cos inverse.
I have a triangle and i know all the lenghts and it's a right angled triange but i want to find out the 1 of the angles.
so i try this math equation a^2 = b^2 + c^2 - 2bc CosA which in thurn leads me to
A = COS^-1 ( a^2 - b^2 - c^2 / 2bc )
how would i implement this?
any help is appericated.. thanks a mill.