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Bitwise & with 0xFF

807601Jun 7 2008 — edited Jun 7 2008

Folks, Looking at a piece of code, didn't understand why do we need to do a bitwise & with 0xFF.

StringBuffer sb = new StringBuffer("F1");
short hexNum = Short.parseShort(sb.toString(), 16);
b[bufIdx] = (byte) (*hexNum & 0xFF*);

As we are casting it to byte, the upper byte would be truncated anyways? If I don't get it right, can someone please explain the logic?

TIA!

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Locked on Jul 5 2008

Added on Jun 7 2008

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